Sure just throw a 1 / sqrt(2 pi) in front of it
Can we normalize science?
August 9, 2026 at 12:36 PM
Sure just throw a 1 / sqrt(2 pi) in front of it
ℹ️🎈sqrt(-jump^2)
nnnv️→Mile
nnnv️→Mile
December 2, 2025 at 8:26 AM
ℹ️🎈sqrt(-jump^2)
nnnv️→Mile
nnnv️→Mile
I found a nice approximation to the integral of projected areas of an SGGX:
integral sqrt( w^T S w ) dw ~= pi * (
(1-1/sqrt3) * ( sqrt(S00) + sqrt(S11) + sqrt(S22) ) +
(1+1/sqrt3) * sqrt( S00 + S11 + S22 ) )
integral sqrt( w^T S w ) dw ~= pi * (
(1-1/sqrt3) * ( sqrt(S00) + sqrt(S11) + sqrt(S22) ) +
(1+1/sqrt3) * sqrt( S00 + S11 + S22 ) )
February 25, 2025 at 9:52 PM
I found a nice approximation to the integral of projected areas of an SGGX:
integral sqrt( w^T S w ) dw ~= pi * (
(1-1/sqrt3) * ( sqrt(S00) + sqrt(S11) + sqrt(S22) ) +
(1+1/sqrt3) * sqrt( S00 + S11 + S22 ) )
integral sqrt( w^T S w ) dw ~= pi * (
(1-1/sqrt3) * ( sqrt(S00) + sqrt(S11) + sqrt(S22) ) +
(1+1/sqrt3) * sqrt( S00 + S11 + S22 ) )
Sure just throw a 1 / sqrt(2 pi) in front of it
Can we normalize science?
August 9, 2026 at 12:36 PM
Sure just throw a 1 / sqrt(2 pi) in front of it
Did you know that we can visually see why sqrt(40)=2sqrt(10)? Let's see how we can visualize rewriting square roots!
September 21, 2025 at 2:08 PM
Did you know that we can visually see why sqrt(40)=2sqrt(10)? Let's see how we can visualize rewriting square roots!
Fun fact: cos(2π/17) can be expressed in terms of radicals. 🧮
February 12, 2026 at 5:19 PM
Fun fact: cos(2π/17) can be expressed in terms of radicals. 🧮
chat is this real
December 22, 2024 at 2:14 AM
chat is this real
introducing a sqrt lifts more detail
September 9, 2026 at 11:11 AM
introducing a sqrt lifts more detail
current_age = sqrt(year)
July 17, 2025 at 10:40 PM
current_age = sqrt(year)
Just discovered a new way to calculate an approx sqrt of a floating point number 5 cycles faster than using the dedicated instruction on the Sega Dreamcast's SH4, by combining the fast inverse sqrt approximation instruction and a multiplication!
#gamedev #retrogaming #retrocomputing #optimization
#gamedev #retrogaming #retrocomputing #optimization
August 29, 2025 at 7:45 AM
Just discovered a new way to calculate an approx sqrt of a floating point number 5 cycles faster than using the dedicated instruction on the Sega Dreamcast's SH4, by combining the fast inverse sqrt approximation instruction and a multiplication!
#gamedev #retrogaming #retrocomputing #optimization
#gamedev #retrogaming #retrocomputing #optimization
Discord is working on LaTeX support!
![LaTeX being rendered in a Discord message:
perplexity(W) = \sqrt[N]{\prod_{i=1}^{N} \frac{1}{P(w_i|w_{i-1})}}](https://cdn.bsky.app/img/feed_thumbnail/plain/did:plc:qbwp3dyywuumct4op7hd5kmq/bafkreidviwcv3fmrowiqdyun5dvff3ibaq4ma76mkpgge5klno2r3wvqiy)
March 5, 2025 at 1:30 AM
Discord is working on LaTeX support!
Gracias a todos por los consejos. Finalmente se queda así:
![Transcripción en markdown y katex:
### *28.* Realiza las siguientes operaciones con potencias y raíces:
#### *28a.* $\sqrt{36} + 3^2 - \sqrt{81}$
#### *28b.* $(\sqrt{25})^2 - 3^2 + (5^2)^2$
#### *28c.* $\sqrt{121} - [\sqrt{100} - \sqrt{81} - (\sqrt{49} - \sqrt{1})]$
#### *28d.* $\sqrt{121} - \sqrt{36} + 3^2 - \sqrt{81}$
#### *28e.* $[(\sqrt{25})^2 - 3^2 + (5^2)^2 - 622]^2$
#### *28f.* $\sqrt{169} - 29 + \sqrt{121} - [\sqrt{100} - \sqrt{81} - (\sqrt{49} - \sqrt{1})]$](https://cdn.bsky.app/img/feed_thumbnail/plain/did:plc:3dp67jb5li3aiut32fvxxija/bafkreihu5bhjtskounqrmrytuc2z32soiqxqsmd4g37skrxsk4hpasd4qe)
February 9, 2025 at 2:40 PM
Gracias a todos por los consejos. Finalmente se queda así:
In Heslach ist Graffiti einfach anders...
September 18, 2025 at 4:08 PM
In Heslach ist Graffiti einfach anders...
2^sqrt(2) is in this set and transcendental unless im missing something no?
September 25, 2026 at 3:28 AM
2^sqrt(2) is in this set and transcendental unless im missing something no?
"Marbles"
vec3 p=(FC.xy*2.-r)/r.y*mat3x2(-8,0,4,7,4,-7),
f=fract(p/3.+.5)-.5;
o=tanh(.5/tan(p.y-t+5.*sqrt(abs(.4-dot(f,f)))+vec4(6,0,.2,0)));
o*=o;
vec3 p=(FC.xy*2.-r)/r.y*mat3x2(-8,0,4,7,4,-7),
f=fract(p/3.+.5)-.5;
o=tanh(.5/tan(p.y-t+5.*sqrt(abs(.4-dot(f,f)))+vec4(6,0,.2,0)));
o*=o;
September 9, 2025 at 3:13 PM
"Marbles"
vec3 p=(FC.xy*2.-r)/r.y*mat3x2(-8,0,4,7,4,-7),
f=fract(p/3.+.5)-.5;
o=tanh(.5/tan(p.y-t+5.*sqrt(abs(.4-dot(f,f)))+vec4(6,0,.2,0)));
o*=o;
vec3 p=(FC.xy*2.-r)/r.y*mat3x2(-8,0,4,7,4,-7),
f=fract(p/3.+.5)-.5;
o=tanh(.5/tan(p.y-t+5.*sqrt(abs(.4-dot(f,f)))+vec4(6,0,.2,0)));
o*=o;
@cervine.online I love how shiny the sqrt looks in the avatar selection screen
January 10, 2025 at 5:52 PM
@cervine.online I love how shiny the sqrt looks in the avatar selection screen