buff.ly/5GjfTRV
You can check out development on XCB here on Eric's YouTube: buff.ly/OV5wHoN
buff.ly/5GjfTRV
You can check out development on XCB here on Eric's YouTube: buff.ly/OV5wHoN
everyone could touch you.
but you couldn’t leave.
bunny 推特@xantheskoolboy
#commanderD
#CB歡唱夜
#森鼠xCB夜0916
everyone could touch you.
but you couldn’t leave.
bunny 推特@xantheskoolboy
#commanderD
#CB歡唱夜
#森鼠xCB夜0916
#Vulkan #GameDev #IndieDev
#Linux #CSharp #DotNet
www.kicad.org/blog/2025/06...
There are workarounds though, such as adding the following environment variables to your application launcher:
GDK_BACKEND=x11
QT_QPA_PLATFORM=xcb
Or from bash:
export GDK_BACKEND=x11
export QT_QPA_PLATFORM=xcb
kicad
www.kicad.org/blog/2025/06...
There are workarounds though, such as adding the following environment variables to your application launcher:
GDK_BACKEND=x11
QT_QPA_PLATFORM=xcb
Or from bash:
export GDK_BACKEND=x11
export QT_QPA_PLATFORM=xcb
kicad
在這「CB歡唱夜」
用一個輕鬆的態度來了這
穿這件也是有樂趣之處
激發著你想掀開的慾望
當然互動的反應讓你驚喜
然後你就看到…
不變的綁了繩 但算是輕鬆自在的
不同的是前面歡唱
被綁的人在後面玩樂
戴著CB不算裸露吧⋯⋯是吧
#commanderD
#CB歡唱夜
#森鼠xCB夜0916
在這「CB歡唱夜」
用一個輕鬆的態度來了這
穿這件也是有樂趣之處
激發著你想掀開的慾望
當然互動的反應讓你驚喜
然後你就看到…
不變的綁了繩 但算是輕鬆自在的
不同的是前面歡唱
被綁的人在後面玩樂
戴著CB不算裸露吧⋯⋯是吧
#commanderD
#CB歡唱夜
#森鼠xCB夜0916
#dungeonmeshi #deliciousindungeon #fanart #chilchuckswife #chilwife #chilchuck #chilchucktims #digitalsketch #artsona #XCB #XeroxCandyBar
#dungeonmeshi #deliciousindungeon #fanart #chilchuckswife #chilwife #chilchuck #chilchucktims #digitalsketch #artsona #XCB #XeroxCandyBar
Yes, no bloated libX11 or GLX. The future is now.
The original cred goes to mmozeiko from Handmade community, I merely ported it away from libx11!
#c #linux #x11 #opengl
Yes, no bloated libX11 or GLX. The future is now.
The original cred goes to mmozeiko from Handmade community, I merely ported it away from libx11!
#c #linux #x11 #opengl
2. HCYB is a parallelogram due to its diagonals bisecting each other. Thus:
- ang. YCB = CBE which = HFE since BCEF is cyclic.
- ang. HFE = HAE (AFHE cyc.) = 90(deg) - ACB. Therefore ACB + YCB = ACY = 90.
2. HCYB is a parallelogram due to its diagonals bisecting each other. Thus:
- ang. YCB = CBE which = HFE since BCEF is cyclic.
- ang. HFE = HAE (AFHE cyc.) = 90(deg) - ACB. Therefore ACB + YCB = ACY = 90.