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Problem TC: O(nlog(Max(nums))) class Solution { public int minCapability(int[] nums, int k) { int index = 0; int low = Integer.MAX_VALUE; int high = 0; for(int i : nums){ low = Math.min(low, i); high = Math.max(high, i); } int val = Integer.MAX_VALUE; while(low<=high){ int mid = (low+high)/2; if(isPossible(mid,nums,k)){ //note: if mid is possible and is not present in nums[] then also it is valid as we will reduce search space low,mid-1 hence we will find the valid value (smaller than current mid) val = Math.min(val,mid); // we have to find min of all the max values possible high = mid-1; } else low = mid+1; } return val; } public boolean isPossible(int target, int arr[], int k){ int count =0; for(int i = 0;i<arr.length;){ if(arr[i]<=target) {/// if arr[i] is less than the guess 'target' then we have to check for next non consecutive index value i = i+2; count++; } else i++;// other wise check for next index value } return count>=k; } }