#root2
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nauteno-kanariya.bsky.social
えーんこんなのあったの ほしい

x.com/poppo_koratt...
root2 (@poppo_koratta) on X
金銀20周年グッズ、再販してほしいと思ってるの私だけじゃないはず…！！🥹 当時はまだフィギュアやグッズ収集にハマってなかったんですよね😂 今このラインナップ見たら欲しいものだらけ…。 特に 「刺繍キーホルダー」と 「アルフの遺跡 パズルコレクション」 これは切実に再販希望です🤣🙏
x.com
August 26, 2026 at 1:50 AM
wawabi.bsky.social
root1と4やばい、多分参利によりルージュが◯されかけて病んで自◯するのはバトエンだよ…タキヤ家と掃除屋がとんでもないことになるよ…😢
root2はルレは夜双に何を言ったんだ…暴れるのは大変危険だよ…
root3だと多分一味はタヒんでるのかな？個人的にこれ見たかったですが百花繚乱がどうなるんですかね…！？
root6で牡丹は入ることになるのかな
August 25, 2026 at 12:31 PM
sousaku777.bsky.social
root1　茄子美参利、鐘日照ルージュ
→ルージュが〇されかけて牡丹が止病み、その場で自〇するBadEnd。

root2　鷹弐夜双、ルーレット
→ルレが夜双の逆鱗に触れてしまい夜双が店内で暴れる。ルレが牡丹を万華鏡で保護するTrueEnd。

root3　富士ノ弌一味、瀧薬世芹&百合
→世芹と百合が一味に責められているのを見て過去の記憶がフラッシュバック、妃咲の両親を〇した理由を思い出して牡丹覚醒、一味を刺して世芹と百合と一緒に帰り、罪に向き合うことを決めたHappyEnd。
August 25, 2026 at 6:29 AM
sousaku777.bsky.social
ネッ友オフ会をしようと柘榴が声をかけ、突然開催されるオフ会。
場所は万華鏡、花斗さんと柘榴、夏凪くんが揃ったあたりで牡丹はやってきます（※ちゃんとした服着てます）
「ども……」みたいな牡丹に柘榴は絡みまくり、たぶん花斗さんも絡みまくる。笑
4人で楽しくオフ会している状況を遠目で見ていたロールは直ぐ様ベルに連絡、さらに果実を経由して皇木に連絡が入り直ぐ様海石榴と渡くんを連れて万華鏡へ。
窓越しに牡丹を視認した3人は直ぐ様中に入ろうとするが扉から出てきた人影に行く手を阻まれる。
3人の行く手を阻んできたのは、和装に身を包んだ小さな少年だった。

root2　鷹弐夜双
August 23, 2026 at 5:14 PM
sousaku777.bsky.social
root1だった場合牡丹は罪の重さに耐えきれず自〇。
root2&5は大まかな流れは違えど最終的には6と同じendです。
root3の場合はベルたんが容赦なくボコボコにして連れ帰り、root4の場合はゆりせりが説得して泣きながら連れて帰ってきてくれるendでした。
August 20, 2026 at 4:24 PM
brandonrohrer.com
An observation that will surprise no one - In five minutes I got ssh requests for the following usernames, all on 5-digit port numbers:

default
admin
admin1
sysadmin
root2
user (twice)
user1
mytest
wangxx
dennis (twice)
ben
September 6, 2025 at 12:40 PM
wacoca.bsky.social
【京都旅】親友と初めての二人きりの旅で羽根を伸ばしまくりました🪽

https://www.wacoca.com/1879891/

今回お邪魔した🥰 一棟貸しのホテル💗 🛏️THE ROOT2 HOTEL 最大5家族とかで泊まれるよ✨ https://theroot2hotel.com/ https://www.instagram.com/the_r [...]
【京都旅】親友と初めての二人きりの旅で羽根を伸ばしまくりました🪽
今回お邪魔した🥰一棟貸しのホテル💗 🛏️THE ROOT2 HOTEL最大5家族とかで泊まれるよ✨https://theroot2hotel.com/https://www.instagram.com/the_root2_hotel/ホテルの1階にあるサラダ・アサイーのお店🥑ROOT2 SEIKAhttps://www.instagram.com/root2seika/🍖和牛ジャンキーhttps://www.instagram.com/wagyu_junkie/🍣手鞠鮨と日本茶 宗田https://www.c-e-p.co.jp/s_t-souden.html最近のシフクテキナユキナ▷▶︎▷▶︎Babe...xoxohttps://babe-xoxo.com/Instagram▷▶︎▷▶︎https://www.instagram.com/yukina1204xoxo/TikTok▷▶︎▷▶︎https://www.tiktok.com/@yukina1204xoxoLINE▷▶︎▷▶︎https://lin.ee/PTkuqvC#木下優樹菜 #ゆきなてきな #PR #vlog #女子旅 #京都 #京都観光
www.wacoca.com
August 23, 2024 at 3:58 PM
yrroi.bsky.social
Notes from the sqrt(2) proofs stream from 2025 08 03. Check out the 2 min preview for free, and the original 1hr 20min VOD available for patreon members in the quoted post below. #math #notes #proof #squareroot #root2 #irrational #rationalnumbers
A rational number can be expressed as a fraction or ratio of integers: a over b, for any a and b that are integers. Prove sqrt(2) is irrational (proof from discover maths): Assume the opposite. Fundamental theory of algebra is that every natural number larger than one can be expressed uniquely as a prime factorization. assume sqrt(2) = a/b is irreducible for any a and b larger than zero. The expression above can be squared on both sides, and reduced to 2b^2 = a^2. Because a/b must be irreducible a and b are both prime, meaning we have two different prime factorizations of the same number. Proof by contradiction, therefore sqrt(2) must be irrational. Second proof (from vihart.): Consider a right angle triangle where the legs are the same length. By the Pythagorean Theorem, the hypotenuse (hyp) must be sqrt(2). If the leg is an odd length, the hyp must be odd, but if the hyp is odd then it cannot be split into the two equal leg lengths. If the hyp is even, then two times the leg length squared must also be even, meaning the leg must be even, which means the triangle can be further reduced until the leg length is odd. By this logic the hyp cannot be odd, nor can it be even, therefore it must be irrational. Third proof (from Vsauce ding!): If the number 2x is even, then we can be certain that the number 2x+1 is odd. An even number squared is even. An odd number squared is odd. Assume sqrt(2) = a/b. Squaring that equation gives 2b^2 = a^2. If we assume a is even, then we can write a as 2 times some other number c, and we can write the previous equation as 2c^2 = b^2. From this b^2 must be even, and b must also be even. If a and b are both even, then a/b is not in its simplest form, breaking our original assumption and proving that sqrt(2) cannot be written as any a/b, and is therefore irrational. Fourth proof (from tipping point math): If a and b are any two integers, then a^2 has an even number of 2's as its factors, and 2b^2 has an odd number of 2's as its factors. From this argument, the absolute value of a^2 - 2b^2 must be larger than or equal to one. Absolute value of sqrt(2)- (a/b), multiplied by the absolute value of sqrt(2) + (a/b) over itself (equating to a multiply by 1/1). Multiply both the numerator and denominator by (b^2/b^2). Reduce this expression to the absolute value of (a^2 - 2b^2) over the absolute value of (b(sqrt(2)b + a). Reduce to the absolute value of( one over b(sqrt(2)b + a)), and realize this expression must be larger than 0, proving sqrt(2) cannot be written as a/b for any integers a and b, as originally assumed. Fifth proof (also from tipping point math): Consider a right isosceles triangle where both legs are the same length. if sqrt(2) = x/y then there must be some a and b integers which can describe the hypotenuse a and the leg b in the triangle's lowest form. If a and b are integers, then a-b must also be an integer. Consider a right isosceles triangle embedded within the previous triangle, where the legs of the smaller triangle are both the integer a-b. The hypotenuse of this smaller triangle must be the remaining part of the larger leg length b, subtracted the smaller leg length a-b, simplified to 2b-a. As the smaller triangle is inscribed into the corner of the larger triangle, the ration between leg and hypotenuse must be the same, sqrt(2), and therefore the form a/b cannot be the lowest form of the triangle, therefore sqrt(2) cannot equal any fraction of integers. Sixth proof (from wrath of math, originally demonstrated in 2000 by Tom Apostol of Caltec): Assume sqrt(2) = a/b, which is the same statement as assuming that there exists an isosceles right triangle with integer sides. Consider scaling up the triangle by some factor b. Legs of length 1 will become length b. Hypotenuse of length sqrt(2) will become length a. From our first assumption, we can also assume there exists a smallest version of the isosceles right triangle with integer sides, running form point A to O to B and back to A again, with the right angle at point O. The angle AO must equal the angle BO, which we will call x. Now consider a circle drawn about the point B, with a radius of BO, sweeping from O to intersect with the hypotenuse AB at some point C. Consider a triangle drawn tangential to that circle, with a right angle at point C, drawn from C to A to the intersection of that tangent with the line AO at some point D. This is a smaller isosceles right triangle with integer sides, and we have reached the proof of absurdity.
July 27, 2026 at 2:56 AM
sils.bsky.social
eaglet.skr.jp/AC/root2.html

個人サイトにラストレイヴンのルート例あるじゃん・・・。感謝・・・
ラストレイヴン ルート例
eaglet.skr.jp
January 2, 2026 at 3:06 PM
mathsadvance.bsky.social
…maybe make some questions specifically with gradients in terms of root2/root3 or fractions like 7/11 and 12/5 and get them to work it out both ways?

It’s reasonable for them to think like that as they want to have to adjust their way of thinking, but they should adjust given time.
September 26, 2024 at 5:03 PM
dansshadow.bsky.social
root2
November 1, 2024 at 8:26 PM
1stclassmaths.bsky.social
I don’t think it is any harder. Everyone I gave it to prior to posting (including students) arrived at the same answer. It depends how to match the ratios together but I think getting root2 : root3 follows easily from sine rule for the right most sides.
January 30, 2025 at 2:23 PM
1stclassmaths.bsky.social
Perhaps I should add to expect a,b,c to be < 10.

36, 12, 18 works but root36 = 6 so if you divide each by root6 you get root6, root2, root3, which is a bit nicer than root36, root12, root18.
January 30, 2025 at 1:38 PM
gatahome.bsky.social
「ホテル リニューアル 宿泊施設」に関する記事です: https://www.s-housing.jp/archives/346313
東寺前のホテルが一棟貸し切りの宿泊施設にリニューアル | 新建ハウジング
ROOT2（京都市）はこのほど、同社が運営するホテル「THE √2 HOTEL」を一棟貸し宿泊施設「√2 Ma
www.s-housing.jp
April 10, 2024 at 10:15 AM
miriamgrace.bsky.social
Likewise cos(5pi/12) computes as 1/4(root2-root6) but it’s a positive answer, I know that bc it’s in the first quadrant so even tho the law of cosines gives a negative I’m just putting positive and vibin
January 27, 2026 at 4:33 AM
miriamgrace.bsky.social
Ok nvm I don’t understand why sin(pi/12) is root3-1/2root2 instead of 1/4(root6 - root2) but they’re literally the same answer and I’ve been tripping for 10 minutes
January 27, 2026 at 4:22 AM
paula-projekt.bsky.social
1<root2<2
1.4<root2<1.5
1.41<root2<1.42
etc.
The number of decimal places is uncountably infinite.
I hope that this was a little helpful. If not, please reply, so that I can do better.
January 18, 2025 at 9:45 PM
toga30848.bsky.social
エモクロア＜声涙の旅路＞
root2終了でセーブ！
PL:yumebonさん、るぅなさん、わし

DL:TaKaさん(作者様)
「今のところ、違うもの持って帰ってきてる」
May 7, 2024 at 4:05 PM
celeryrealfood.bsky.social
I might just stick with these icons to be used in root2.
I'll probably get an icon artist to do the other icons in Death Knell and or Pureitoi

Idk yet
October 25, 2024 at 4:26 PM
celeryrealfood.bsky.social
Also ig I'll post this too for #celerystackpack #fnf

I made these as like a new change to the icons, for Root2 but idk if it would work well sense mainly the fnf icon style is very different so...idk

What do y'all think
October 25, 2024 at 12:20 AM
celeryrealfood.bsky.social
Though really I might need to try getting some progress done for Pureitoi sense...it's the only song in Pack 1 that isn't really finished besides an inst. But I'm sure that song will get his time, hopefully

Right now Root2 and Death Knell are the main focuses!!
October 24, 2024 at 11:05 PM
celeryrealfood.bsky.social
Actually I might make this a help wanted post because I really need like a background artist for Root2 rn 🙏

Like the background and the sprites are the only things needed for Root2 to be done, the song and chart has been done a long time ago
celeryrealfood.bsky.social ☘️ ︳celery dude™ @celeryrealfood.bsky.social · Oct 21
like i really wanted to make like the background for root2 be like all aesthetic and shit like how fnf encore does it but AAAAAAAAAAAAAAAAAAA i dont have the right tools to do so
October 22, 2024 at 1:22 AM
celeryrealfood.bsky.social
another thing for uh #celerystackpack

im having a friend assist on making the sprites for root2

and when i was like helping to give feedback for poses to make sure it flows i accidenly made a semi okish hand for pointing up and also clenching and its so funny cuz how did i manage to do this bro
October 21, 2024 at 10:36 PM